Ultrasonic Speaker Calibration Adventure, Part 2

filter efficacy

So I had a solution that got the ouput I wanted but it was just too slow. I ran some profiling on my code (using cProfile and RunSnakeRun) and found that most of my time was being spent in my frequency adjustment function, of course. I am processing many stimuli in a batch, but the calculations are independent – perfect candidate for multiprocessing, I thought. So I wrote a little code to spin off a bunch of processes, and my code executed faster… sometimes. Depending on the type of signal I was calibrating, the increase in performance was somewhere between 1-10x. As it turns out, I should be fixing my shitty, slow algorithm, instead of trying to squeeze better performance out of it.

Hmm, so what was the difference between my stimuli that had startling performance differences? It was taking ~5 seconds to calibrate 200 tone stimuli, and ~5 minutes to calibrate 200 stimuli from a recording file of the same duration. As input to the calibration functions, both types are just represented by a vector of numbers.

Although they were the same duration, what I had overlooked was sampling rate. The sythnthesized stimuli had a constant samplerate that I set, but the recording files use the samplerate that they were recorded at, which was different. Thus, the length of the vector that gets input into the FFT function was a different length, and very inefficient in some cases.

The answer was to institute zero-padding. Any text on the FFT will mention that it is more efficient for input with a length of 2n, and this experience very much illustrated this for me. Here is what I replaced the beginning of my multiply_frequencies code with:

 
def multiply_frequencies(signal, fs, attendB):
    npts = len(signal)
    padto = 1<<(npts-1).bit_length() # next highest power-of-2


    X = np.fft.rfft(signal, n=padto)
    ...

Ahhh Much better, now all my execution times are on the scale of seconds, instead of minutes. However, now having brought DSP into my conversational discourse, people were throwing out terms like “convolve” and “FIR”, and I had a feeling that a better solution was waiting for me in these mysterious words. So, after some more reading, I looked into creating a filter out of my frequency attenuation curve.

Creating a Digital Filter

To understand how to do this I must first explain some DSP concepts.

Some Fundamentals

First I want to define the delta function, also known as the unit impulse, which is a signal with a single non-zero point of value one at time zero. An impulse response is the ouput of a system, where the input is the unit impulse.

Any digital signal can be decomposed into a group of impulses, or shifted and scaled delta functions. Add this group of impulses back together and you receive your original signal.

A necessary condition is that we are working with a linear time-invarient system. This means that if an input to the system is shifted and/or scaled, that the output of the system would also be shifted/scaled by the same amount. The important result from the property of linear time-invarience, is that its impulse response contains all the necessary information about a system. If you know a system’s impulse response, you immediately know how it will react to any impulse. So, if we know the response to an impulse, and we know that the signal is just a collection of impulses, we can shift and scale the impulse response according to the points of our input function and add together the results to get the total response for our input function.

This sounds great, but you may be wondering “Ok, how do I DO that?”, to answer that we must introduce a mathmatical operator you may or may not be familiar with, called convolution. It was new to me, so I am going to explain it.

Convolution is represented by the symbol in math notation (not to be confused with multiplication in code). In it’s discrete form, it takes two signals and produces a third signal as output. The length of the ouput signal will be the addition of the length of the two input signals minus one. There are two ways to think about and implement convolution.

The first way, the input side algorithm, involves analyzing how each sample of the input signal contributes to many points in the output signal. For each point in the (first) input signal you multiply it by each point in the second signal and add up all the results in place. For me, it helps to see this in code:

 
def convolve_input(a,b):
    output = np.zeros((len(a)+len(b)-1,))
    for i in range(len(a)):
        for j in range(len(b)):
            output[i+j] = output[i+j] + ( a[i] * b[j] )
    return output


x = [0, -1, -1.2, 2, 1.4, 1.4, 0.6, 0, -0.5]
# h = [1, -0.5, -0.2, -0.1]

h = [0.25, 0.25, 0.25, 0.25]

y0 = convolve_input(x, h)

#####plot results#######

col0 = len(x)
col1 = len(x) + len(h)
colspan = len(x) + len(h) + len(y0)
plt.figure(figsize=(20,5))
gs = plt.GridSpec(1,colspan)
plt.subplot(gs[0,:col0])
plt.plot(x, 's', ms=10)
plt.ylim(-1.5, 2.5)
plt.subplot(gs[0,col0:col1])
plt.plot(h, 's', ms=10)
plt.ylim(-1.5, 2.5)
plt.subplot(gs[0,col1:])
plt.plot(y0, 's', ms=10)
plt.ylim(-1.5, 2.5)

convolution example

The second way, the output side algorithm, looks at how each sample in the ouput receives information from the many points in the input signal. This is the more standard way to define convolution, and in its discrete and finite form, it is represented by the equation:

 
def convolve_output(a,b):
    output = np.zeros((len(a)+len(b)-1,))
    for i in range(len(output)):
        for j in range(len(b)):
            if i-j < 0:
                continue
            if i-j >= len(a):
                continue
            output[i] = output[i] + a[i-j] * b[j]
    return output

Here we are looping over every ouput point, and adding up all points in the input that multiply together at that point. If you were to run through the example data, you would get identical results to the first method.

When we are dealing with signals and filters, the filter signal is typically much shorter than the data signal. For a filter signal of length M, note that the first and last M-1 samples of the ouput signal are trying to receive input from non-existent samples from the input signal. When this happens we say that the impulse response is not fully immersed in the input signal. These samples of the output are effectively garbage, and will we toss them out when we use this later.

In the example data I gave, the second signal is acting as a moving average filter. You can see that the output signal is a smoothed version of the first input signal. This is the case whenever one of our input signals has identical points of value 1/length of the signal.

The moral of this convoluted story (hehe) is that you take in two signals and produce a third from them. It is commutative, so it doesn’t matter which input signal is which, but for the purposes of our filter, we can think of one of the input signals as the input to the system and the other input signal as performing some shifting and scaling.

Hopefully this is at least somewhat clear, not looking for crystal, I’ll settle for murky water. Check out a more in depth explainantion here.

###Back to our Filter

Since we know that the impulse response contains all information about a system, we can use the DFT on the impluse response to get the frequency response of the system, since the DFT converts time domain information into frequency domain information. Therefore, it follows that we can get the impulse reponse by taking the IDFT of the frequency response (which we already have, see the prequel). Thus, we can determine the impulse response, and convolve this with our stimuli signals, to receive our calibrated output.

Since the impulse response, in theory, is infinite, and we need to deal with finite signals, as a matter of practicality we can truncate the impluse response to a length that will still produce the frequency response we want, to within an acceptable accuracy. This is what I get when I estimate the impulse response from the IFFT of the frequency response.

An important step in between performing the IFFT and truncating it is to rotate the vector to create a causal filter

 
from spikeylab.tools.audiotools import tukey

def impulse_response(genrate, fresponse, frequencies, frange, filter_len=2**14):
    """
    Calculate filter kernel from attenuation vector.
    Attenuation vector should represent magnitude frequency response of system
    
    Args:
        genrate (int): The generation samplerate at which the test signal was played
        fresponse (numpy.ndarray): Frequency response of the system in dB, i.e. relative attenuations of frequencies
        frequencies (numpy.ndarray): corresponding frequencies for the fresponse
        frange ((int, int)) : the min and max frequencies for which the filter kernel will affect
        filter_len (int, optional): the desired length for the resultant impulse response
        
    Returns:
        numpy.ndarray : the impulse response
    """

    freq = frequencies
    max_freq = genrate/2+1

    attenuations = np.zeros_like(fresponse)
    # add extra points for windowing

    winsz = 0.05 # percent

    lowf = max(0, frange[0] - (frange[1] - frange[0])*winsz)
    highf = min(frequencies[-1], frange[1] + (frange[1] - frange[0])*winsz)

    # narrow to affect our desired frequency range

    f0 = (np.abs(freq-lowf)).argmin()
    f1 = (np.abs(freq-highf)).argmin()
    fmax = (np.abs(freq-max_freq)).argmin()
    # also window section

    attenuations[f0:f1] = fresponse[f0:f1]*tukey(len(fresponse[f0:f1]), winsz)

    freq_response = 10**((attenuations).astype(float)/20)
    
    # can only filter for between 0 and Nyquist

    freq_response = freq_response[:fmax]

    impulse_response = np.fft.irfft(freq_response)
    
    # rotate to create causal filter

    impulse_response = np.roll(impulse_response, len(impulse_response)//2)

    # truncate

    if filter_len > len(impulse_response):
        filter_len = len(impulse_response)
    startidx = (len(impulse_response)//2)-(filter_len//2)
    stopidx = (len(impulse_response)//2)+(filter_len//2)
    impulse_response = impulse_response[startidx:stopidx]
    
    # Also window the impulse response

    impulse_response = impulse_response * tukey(len(impulse_response), 0.05)

    return impulse_response

It should be possible to reduce the size of the attenuation vector to improve performance, as I would then have a shorter vector to convolve with my signal. Zero values at the ends of the filter do not add anything to the convolution, so they can be safely truncated, however, it was worth playing around with lengths, as some very small values close to zero can have a significant effect on the filter. More about this later.

Now that we have a filter kernel for our system, I can convolve this with my outgoing signal to get a calibrated signal. Here is a script which brings it all together. Note that this is almost identical to the demo script from the previous post, except where noted:

 
from scipy import signal
import matplotlib.pyplot as plt
from test.scripts.util import play_record
from spikeylab.tools.audiotools import attenuation_curve # defined in previous post


out_voltage = 0.65 # amplitude of signal I want to generate

mphone_sens = 0.00407 # mV/Pa calibrated micrphone sensitivity (for plotting results)


fs = 5e5
duration = 0.2 #seconds

npts = duration*fs
t = np.arange(npts).astype(float)/fs
out_signal = signal.chirp(t, f0=5000, f1=100000, t1=duration)
# scale to desired output voltage

out_signal = out_signal*out_voltage

# windowing (taper) to avoid clicks

rf_npts = 0.002 * fs
wnd = signal.hann(rf_npts*2) # cosine taper

out_signal[:rf_npts] = out_signal[:rf_npts] * wnd[:rf_npts]
out_signal[-rf_npts:] = out_signal[-rf_npts:] * wnd[rf_npts:]

# play signal and record response -- hardware dependent

response_signal = play_record(out_signal, fs)

# we can use this signal, instead of white noise, 

# to generate calibration vector (range limited to chirp sweep frequencies)

attendb, freqs = attenuation_curve(out_signal, response_signal, fs, calf=15000)

# -----difference from previous post -------

filter_kernel = impulse_response(fs, attendb, freqs, frange=(5000,100000))
calibrated_signal = signal.fftconvolve(out_signal, filter_kernel) #faster convolution function

# remove those 'garbage' points

calibrated_signal = calibrated_signal[len(filter_kernel)/2:len(calibrated_signal)-len(filter_kernel)/2 + 1]
# ------------------------------------------


calibrated_response_signal = play_record(calibrated_signal, fs);

###########################PLOT######################################

# see previous post for plotting code 

spectrogram

So this looks like it’s working. I still need a measure of how “good” the calibration is. After all, this is science, so “this one looks better than that one”, isn’t really a sufficient measure. I calculated the error between my desired and recorded response using the mean square error: $MSE = \frac{1}{n} \sum_{n=0}^{n}(\hat{Y_i} - Y_i)^2$. In the data plot below, I added an x to indicate the measure for the multiplication method from the last post. As you can see, the filter kernel just needs to be a minimum size, > 2400, to get the best results.

filter efficacy

I also calculated the MSE of an uncalibrated signal, which came in at 46.63, which means that our calibrated signals produce a much more accurate sound. This data was generated using a chirp stimulus with a duration of 200ms and a samplerate of 500kHz, although other stimuli were examined, to comparable results.

Now, I need to determine if this method is actually faster than before. I ran the calibration using different kernel lengths, and also using the multiplication method from before. Each data point represents the time taken to execute 200 iterations of applying the filter to a sample signal:

filter performance

Thus, using a digital filter, we can be about twice as fast as our previous method of multiplying frequencies. However, there is that sharp jump where the execution time doubles, between 214 and 215. Drilling down, I found this to be exactly between a filter length of 31073 and 31074 (although yesterday it was between 24289 and 24290 :/ ). This was regarless of the signal length it was convolved with. I made sure to include filters lengths that are a power of 2, since I was employing numpy’s fftconvolve, and signal length could be a performance factor. I also padded the signal I am convolving with to be a power of two, but that seemed to be worse, with smaller filters jumping up to the slower time. I do not understand why this is. If you think you know why, please leave a comment!

Luckily, we know from the efficacy evaluation that we can use a shorter filter. So, I can use a filter with a size of 2400 - 24289 and achieve good results with respect to frequency response and performance.

Now I have a calibration procedure that produces a signal much closer to the desired sound, and in a resonable amount of time. What this all means, is that I can now go get in my hammock and take a nap.


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